首页> 外文OA文献 >Sufficient condition for nonexistence of symmetric extension of qudits using Bell inequalities
【2h】

Sufficient condition for nonexistence of symmetric extension of qudits using Bell inequalities

机译:不存在qudits对称扩展的充分条件   使用贝尔不等式

代理获取
本网站仅为用户提供外文OA文献查询和代理获取服务,本网站没有原文。下单后我们将采用程序或人工为您竭诚获取高质量的原文,但由于OA文献来源多样且变更频繁,仍可能出现获取不到、文献不完整或与标题不符等情况,如果获取不到我们将提供退款服务。请知悉。

摘要

We analyze the connection between Bell inequality violations and symmetricextendibility of quantum states. We prove that 2-qubit reduced states ofmultiqubit symmetric pure states do not violate the BellClauser-Horne-Shimony-Holt (CHSH) inequality. We then prove the more generalconverse that any 2-qubit state that violates the CHSH inequality cannot have asymmetric extension. We extend our analysis to qudits and provide a test forsymmetric extendibility of 2-qudit states. We show that if a 2-qudit Bellinequality is monogamous, then any 2-qudit state that violates this inequalitydoes not have a symmetric extension. For the specific case of 2-qutrit states,we use numerical evidence to conjecture that theCollins-Gisin-Linden-Massar-Popescu (CGLMP) inequality is monogamous. Hence,the violation of the CGLMP inequality by any 2-qutrit state could be asufficient condition for the nonexistence of its symmetric extension.
机译:我们分析了贝尔不等式违反与量子态的对称可扩展性之间的联系。我们证明了多量子位对称纯态的2量子位简化态不违反BellClauser-Horne-Shimony-Holt(CHSH)不等式。然后,我们证明了更为普遍的反面,即任何违反CHSH不等式的2量子位状态都不能具有不对称扩展。我们将分析扩展到Qudit,并提供2 Qudit状态对称扩展性的测试。我们证明,如果一个2阶Bellinequality是一夫一妻制,那么任何违反此不等式的2量子态都不会具有对称扩展。对于2-qutrit态的特定情况,我们使用数值证据来推测,Collins-Gisin-Linden-Massar-Popescu(CGLMP)不等式是一夫一妻制。因此,任何2-qutrit状态违反CGLMP不等式可能是其对称扩展不存在的充分条件。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
代理获取

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号